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Q1) write the following statement in ' if- then' form:-
1)The opposite angles of a parallelogram are congruent.
2) the diagonals of a rectangle are congruent.
3)In an isosceles triangle, the segment joining the vertex and the midpoint of the base is perpendicular to the base.
note:(those who know only answer)
maths part 2 (Geometry)9th syllabus.
Answers
Answer:
1. Parallelograms: The Two Pairs of Opposite Angles are Congruent. A parallelogram is defined as a quadrilateral where the two opposite sides are parallel. One of the properties of parallelograms is that the opposite angles are congruent, as we will now show
2. The first way to prove that the diagonals of a rectangle are congruent is to show that triangle ABC is congruent to triangle DCB. Since ABCD is a rectangle, it is also a parallelogram. Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruent.
3. Isosceles Triangles: the Median to the Base is Perpendicular to the Base. In a triangle, a line that connects one corner (or vertice) to the middle point of the opposite side is called a median.
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Step-by-step explanation:
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Answer:
1). Parallelograms: The Two Pairs of Opposite Angles are Congruent
By Ido Sarig, BSc, MBA
A parallelogram is defined as a quadrilateral where the two opposite sides are parallel. One of the properties of parallelograms is that the opposite angles are congruent, as we will now show.
Since this a property of any parallelogram, it is also true of any special parallelogram like a rectangle, a square, or a rhombus,
Problem
ABCD is a parallelogram, AD||BC and AB||DC. Prove that ∠BAD ≅ ∠DCB and that ∠ADC ≅ ∠CBA
parallelogram with diagonal
Strategy
There are two ways to go about this. The first is to use congruent triangles to show the corresponding angles are congruent, the other is to use the Alternate Interior Angles Theorem and apply it twice.
2). The first way to prove that the diagonals of a rectangle are congruent is to show that triangle ABC is congruent to triangle DCB
Here is what is given: Rectangle ABCD
Here is what you need to prove: segment AC ≅ segment BD
Since ABCD is a rectangle, it is also a parallelogram.
Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruent.
BC ≅ BC by the Reflexive Property of Congruence.
Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.
∠ABC ≅ ∠DCB since all right angles are congruent.
Summary
segment AB ≅ segment DC
∠ABC ≅ ∠DCB
BC ≅ BC
Therefore, by SAS, triangle ABC ≅ triangle DCB.
Since triangle ABC ≅ triangle DCB, segment AC ≅ segment BD
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