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Step-by-step explanation:
Given:-
Tina's house is 1 9/10 km away from her school.
She walked some distance and took a bus for
1 1/2 km to reach the school.
To find:-
How far did she walk.
Solution:-
The distance between the school and Tina's house = 1 9/10 km= 19/10 km
Distance travelled by bus =1 1/2 km= 3/2 km
Distance travelled on foot =19/10-3/2
=>19/10-3/2
LCM of the denominators 10 and 2 =10
=>[(19×1)-(3×5)]/10
=>(19-15)/10
=>4/10
=>2/5 km
Answer:-
Tina walked 2/5 km
so,The distance covered by Tina on foot is 2/5 km
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