Question

pls please answer my question as fast assss​

Answer 1

Step-by-step explanation:

Let age of B =x years

Age of A =x+9 years

After 10 years,

Age of B =x-10 years

Age of A=x+9+10

=x+19 years

According to question,

x+19=2(x-10)

x+19=2x-20

x-2x= -20-19

-x= -39

x=39

Age of B=39 years

Age of A=39+9 =48 years

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Answer 2

Question:-

A is now 9 years older than B. In 10 years, A will be twice as old as B was 10 years ago. Find their present ages.

Answer:-

Present age:-

Let the age of B be x years

Then age of A = (x + 9) years

10 years later:-

Age of A = x + 9 + 10 = (x + 19) years

Age of B = x + 10 = (x + 10) years

10 years ago:-

Age of A = x + 9 - 10 = (x - 1) years

Age of B = (x - 10) years

Given: In 10 years, A will be twice as old as B was 10 years ago

A/q

x + 19 = 2(x - 10)

=> x + 19 = 2x - 20

=> x = 39 years

Present ages:-

• Age of A = x + 9 = 48 years
• Age of B = x = 39 years