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X= 40 degrees
y=40degrees please mark an brainliest answer please
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1
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Let the centre point be O
Since , Diagonals of a rhombas bisect each other at 90°
So , ANGLE SOR = ANGLE QOR = ANGLE POQ = ANGLE SOP
So , In ∆ SOR
ANGLE SOR + ANGLE OSR + ANGLE SRO = 180°
90° + x + 40° = 180°
130° + x = 180°
x = 180° - 130°
x = 50°
Since , In a rhombus opp. sides are parallel
So , PQ ll SR and PR is a transversal
Then , ANGLE QPO = ORS = 40°
SO , y = 40°
Therefore , x = 50° , y = 40°
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