Question

pls pls answer fast its an emergency​

Answer 1

Answer:

Let the one's digit be x and ten's place digit be y.

Number = 10y + x

Sum of digits = 5

x + y = 5 --> ( i )

10 x + y - ( 10y + x ) = 9

10x + y - 10y - x = 9

9x - 9y = 9

x - y = 1 --> ( ii )

Adding both equations,

2x = 6

x = 6/2 = 3

Now, putting value of x in any equation, let ( i ),

3 + y = 5

y = 5 - 3 = 2

y = 2, x = 3

Number = 10× 2 + 3 = 23

Number = 23