pls pls answer this question and ill mark u brainliest if the answer is correct :-
In the circuit shown in figure, the reading of the voltmeter V will be :
(A) 4 V (B) 2 V (C) 6 V (D) 3 V
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Explanation:
Current I = 12/300 = 40 mA
V=IR
voltage drop at 200 ohm resistor = 40 mA ×200ohm
= 8V
remaining = 12-8 =4V
therefore reading of voltmeter = 4V
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