Question

Pls pls answer this question

Please answer it guys!!!

Answer 1

$\underline{Here's \: the \: answer}$

Let the present ages of Manish and Savita be
'x' years and 'y' years respectively.

According to the first condition,

$\tt{x + y = 31}...(eq.1)$

Therefore,

Manish's age = ( x - 3 ) years
Savita's age = ( y - 3 ) years

According to the second Condition,

$\tt{(x - 3) = 4(y - 3)}$

$\tt{x - 3 = 4y - 12}$

$\tt{x - 4y = - 12 + 3}$

$\tt{ \therefore \: x - 4y = 9}...(eq.2)$

Now,

Subtracting (eq. 2) from (eq. 1) , we get
$\: \: \: \: \: \: \: \: \tt{x + y = 31} \\ - \: \: \: \: \tt{x - 4y = - 9} \\ - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \tt{ 5y = 40}$

$\tt{ \therefore \: y= \frac{40}{5} = 8}$

Now,

Substituting y = 8 in (eq. 1) , we get

$\tt{x + 8 = 31} \\ \\ \tt{x = 31 - 8} \\ \\ \tt{x = 23}$


Therefore,

The present ages of Manish and Savita are 23 years and 8 years respectively.

Thanks!