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r=0.5A°=0.5*10^-10m
volume of 1 H-atom=(4/3)π(0.5*10^(-10)m^3
=(4/3)(22/7)×(1/8)×10^-30m^3
=11/7×10^(-30)m^3
volume of 1mole of hydrogen atom=6.022×10^23×(11/7)×10^(-30)
=9.46×10^(-7)m^3
volume of 1 H-atom=(4/3)π(0.5*10^(-10)m^3
=(4/3)(22/7)×(1/8)×10^-30m^3
=11/7×10^(-30)m^3
volume of 1mole of hydrogen atom=6.022×10^23×(11/7)×10^(-30)
=9.46×10^(-7)m^3
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