Question

pls pls help me I will mark u brainylists

Answer 1

2 sin - 2 =cos
sin + 2 cos = sin + 4sin- 4= 5 sin -4

Answer 2

Hope u like my process
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$= > \bf2 \sin( \theta ) - \cos( \theta ) = 2 \\ \\ \bf \underline{squaring \: \: both \: \: sides \: \: } \\ \\ = > \: {(2 \sin( \theta ) - \cos( \theta ) )}^{2} = {2}^{2} \\ \\ or. \: \: 4 \sin ^{2} ( \theta ) + \cos ^{2} ( \theta ) - 4 \sin( \theta ) \cos( \theta ) = 4 \\ \\ or. \: \: 4(1 - \cos ^{2} ( \theta ) ) + (1 - \sin ^{2} ( \theta ) ) - 4 \sin( \theta) \cos( \theta ) = 4 \\ \\ or. \: \: 4 - 4 \cos ^{2} ( \theta ) + 1 - \sin ^{2} ( \theta ) - 4 \sin( \theta ) \cos( \theta ) = 4 \\ \\ or. \: \: 4 \cos ^{2} ( \theta ) + \sin ^{2} ( \theta ) + 4 \sin( \theta ) \cos( \theta ) = 1 \\ \\ or. \: \: {( \sin( \theta ) + 2\cos( \theta )) }^{2} = {1}^{2} \\ \\ or. \: \: \bf \: \sin( \theta ) + 2 \cos( \theta ) = \sqrt{1} = \underline{1}$
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