Question

pls pls its urgent pls ​

Answer 1

Answer:

Step-by-step explanation:

2∧2n-1* 4∧1-n

=2∧2n-1*2∧2-2n

=2∧(2n-1+2-2n)

=2∧1

=2

Answer 2

${2}^{2n - 1} \times {2}^{2-2n} \\ {2}^{1}$

in first step I took wrote 4 as 2^2....hope you would understand ....