Math, asked by Anonymous, 10 months ago

pls pls pls pls.........​

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Answered by inamul7
18

Answer:

Circumference of the track = 2πr

2 \times  \frac{22}{7}  \times 21

=2×22×3

= 44×3

=132m

therefore distance = 132 m

speed =8km/hr

= 8×1000m/3600sec

= 2.22m/sec

speed = distance/time

time = distance/speed

=132m/2.22

=59.4 sec

Step-by-step explanation:

hope it helps yrr

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Answered by Anonymous
88

Answer:

Step-by-step explanation:

Circumference of the track = 2πr

2 × 22/7 × 21

=2×22×3

= 44×3

=132m

therefore distance = 132 m

speed =8km/hr

= 8×1000m/3600sec

= 2.22m/sec

speed = distance/time

time = distance/speed

=132m/2.22

=59.4 sec

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