Question

pls pls pls pls pls pls pls pls answer Q-If alpha and beta are the zeroes of the quadratic polynomial 3x2+5x+7, Evaluate 1/alpha^3 + 1/beta^3
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Answer 1

Step-by-step explanation:

Given expression,3x^2+5x+7

let it be equal to zero

3x^2+5x+7=0

here, a=3;b=5;c=7

The value of x is,

x=[-b±√b^2–4ac]/2a

x=[-5±√25–84]/6

x=[-5±√-59]/6

x=[-5± i √59]/6………………………………………….where i is the imaginary number{i=√-1}

x=[-5+i√59]/6 , x=[-5-i√59]/6

therefore; α=[-5+i√59]/6 ; β=[-5-i√59]/6

α^3=[-125 -i 59√59+i15√59(i√59–5)]\6……………………………….{i^3=-i}

Therefore,(α^3)+1=[-119 -i 59√59+i15√59(i√59–5)]\6

β^3=[-125 -i 59√59+i15√59(i√59+5)]\6