Math, asked by duddhdh9, 5 months ago

pls pls pls pls pls pls pls pls pls
give me the answer​

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Answers

Answered by hassanalihassanali06
1

Answer:

In 1st)88^2=(90-2)^2=90^2+2^2-2×90×2

In 3rd)(x-y)^2=x^2+y^2-2×x×y

in 2nd)=(90-6)^2=90^2+6^2-2×90×6

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