Question

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Question no.5​

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\bf\red{ \mapsto \: {4x}^{2} + 4 \sqrt{3}x + 3 = 0} \\ \\ \bf\pink{ \mapsto \: \frac{ {4x}^{2} }{4} + \frac{4 \sqrt{3}x }{4} + \frac{3}{4} = 0} \\ \\ \bf\blue{ \mapsto \: {x}^{2} + \sqrt{3}x + \frac{3}{4} = 0 } \\ \\ \bf\orange{ \mapsto \: {x}^{2} + 2.x \frac{ \sqrt{3} }{2} + ({ \frac{ \sqrt{3} }{2} })^{2} - ({ \frac{ \sqrt{3} }{2} })^{2} + \frac{3}{4} = 0} \\ \\ \bf\green{ \mapsto \: {(x + \frac{ \sqrt{3} }{2} )}^{2} = ({ \frac{ \sqrt{3} }{2} })^{2} - \frac{3}{4} } \\ \\ \bf\pink{ \mapsto \: {x + (\frac{ \sqrt{3} }{2} })^{2} = \frac{3}{4} - \frac{3}{4} } \\ \\ \bf\red{ \mapsto \: {(x + \frac{ \sqrt{3} }{2} )}^{2} = 0} \\ \\ \bf\purple{ \mapsto \: {(2x + \sqrt{3} )}^{2} = 0} \\ \\ \bf\red{ \mapsto \: (2x + \sqrt{3} )(2x + \sqrt{3} ) = 0} \\ \\ \bf\blue{ 2x + \sqrt{3} \implies\:0 } \\ \\ \bf\pink{ \mapsto \:x = \frac{ - \sqrt{3} }{2} } \\ \\ \bf\orange{ 2x + \sqrt{3} \implies\:0 } \\ \\ \bf\green{ \mapsto \:x = \frac{ - \sqrt{3} }{2} }$

$\large\boxed{ \fcolorbox{red}{lime}{hope \: it \: help \: you}}$