Question

pls pls pls someone answer it quickly ​

Answer 1

$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

Length of the wire = 264 m

$\underline \mathbb{TO \: FIND:-}$

Area of ground enclosed by the wire.

$\underline \mathbb{FORMULA:-}$

Circumference of the circle = 2 π r ( r is Radius)

Area of the square = π $r^2$

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

Length of the wire is equal to the circumference of the circle.

So,

$2\pi \: r = 264 \\ \\ \implies \: 2 \times \frac{22}{7} \times r = 264\\ \\ \implies \:r = 264 \times \frac{1}{2} \times \frac{7}{22} \\ \\ \implies r = \:42m$

And now we have to find the area.

$Area \: = \pi \: {r}^{2} \\ \\ \implies \: Area \: = \frac{22}{7} \times 42 \times 42\\ \\ \implies \: Area = 5544 \: {m}^{2}$

$\underline \mathbb{ANSWER:-}$

$\implies \boxed{\: Area = 5544 \: {m}^{2} }$