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Step-by-step explanation:
qus incomplete
If u are asking to find its derivative, take log on both side
y = x ^sinx + tanx ^x
log y = sinx logx + x log tanx
Derivating w.r.t. x
1/y dy/dx = sinx * 1/x + logx * cosx + x * 1/tanx * sec²x + tanx
= sinx/x + cosx logx + x tanx
dy/dx = (x ^sinx + tanx ^x) [sinx/x + cosx logx + x tanx]
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