Question

pls proove its right.Q4

Answer 1

We know that sum of lengths of two sides of a triangle is greater than the length of the third side.

So,  AB + BC > AC  --------------- (i)
       AB + AB > BD  -------------- (ii)
       CD + BC > BD  ------------- (iii)
       AD + DC > AC  ------------- (iv)

Now solve all these 4 equaltions,

= 2AB + 2BC + 2CD + 2AD > 2AC + 2BD 

= 2(AB + BC + CD + AD) > 2(AC + BD) 

= (AB + BC + CD + AD) > (AC + BD)