Question

Pls prove it Guys.,..........​

Answer 1

Answer:

(1)

LHS: =(sin^2θ/cosθ)+cosθ

=(sin^2θ+cos^2θ)/cosθ

in^2θ+cos^2θ)/cosθ = 1/cosθ

in^2θ+cos^2θ)/cosθ = 1/cosθ =secθ

Thus, LHS = RHS

Step-by-step explanation:

Answer:

(2)

LHS: =cos^2θ(1+tan^2θ)

=cos^2θ{1+(sin^2θ/cos^2θ)}

=cos^2θ × {(sin^2θ.cos^2θ)/cos^2θ}

=cos^2θ × sin^2θ

=1

Thus, LHS = RHS