Question

pls provide full solution ​

Answer 1

when the car travel in same direction Relative Speed is x−y

Dist=100km

t=5 hours

∴  Dist =S×T

100=(x−y)5

x−y=20⟶(I)

when car travel in opp direction Relative Speed is x+y

Dist=100km

t=1 hours

Dist=ST

100=(x+y)1

x+y=100⟶(II)

Solving (I) & (II)

x−y=20

x+y=100

   2x=120

x=60km/h

y=40km/h

Speed of the car at A =60 km/h

Speed of the car at B=40 km/h

The difference of speeds is 60−40=20