Math, asked by vasanthiraja14, 3 days ago

pls put clearly ..thanks for helping

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Answered by preeti353615
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Answer:

  • (8xy-4y)^2 + 128xy^2 = (8xy + 4y)^2
  • If the capacity of a rectangular cistern in liters whose dimensions are 11.2m × 6m × 5.8m, then the area of the iron sheet required to make the cistern is 266.72 sq cm.

Step-by-step explanation:

1) Show that (8xy-4y)^2 + 128xy^2 = (8xy + 4y)^2

LHS = (8xy-4y)^2 + 128xy^2 \\= (8xy)^2 - 2 (8xy)(4y)  + (4y)^2  + 128xy^2\\= (8xy)^2 - 64xy^2  + (4y)^2  + 128xy^2\\= (8xy)^2 - 64xy^2 + 128xy^2 + (4y)^2  \\= (8xy)^2 + 64xy^2  + (4y)^2  \\=(8xy +4y)^2

= RHS

(8xy-4y)^2 + 128xy^2 = (8xy + 4y)^2

Hence proved.

2) The dimensions of rectangular cisterm is 11.2× 6 × 5.8

Volume is given by l×b×h=11.2 × 6×5.8=389.76

Lateral surface of Cuboid is given by 2h(l+b)=2(5.8)(11.2+6)=11.6(17.2)=199.52 sq cm.

The base area is given by l×b=11.2 × 6=67.2 sq. cm.

The total area of iron sheet required is 199.52+67.2=266.72 sq cm.

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