Pls quick
Maths problem
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Step-by-step explanation:
A+B+C =180°
B+C =180-A
1/2(B+C) = 180/2 - A/2 [multiple 1/2
on both sides]
B/2+C/2 =90-A/2
tan (B/2+C/2) = tan (90-A/2) [ multiple with tan on both sides]
tan(B/2+C/2) = cot (A/2) proved
Hope it's helpful
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