Question

pls refer the Attachment
only correct answer
and don't Spam!!!!!!​

Answer 1

Answer:

1) $-\sqrt{3}$ and $-2\sqrt{3}$

2) $2\sqrt{3}$ and $-5\sqrt{3}$

Step-by-step explanation:

Using discriminant method:

a = 1, b = $3\sqrt{3}$, c = 6

first we calculate the discriminant:  

$b^{2} - 4ac$ = $3\sqrt{3} ^{2} - 4*1*6$

             = 27 - 24

             = 3

$\sqrt{b^{2} -4ac }$ = $\sqrt{3}$

Roots of the equation are:

root1 =  $\frac{-b + \sqrt{b^{2} -4ac }}{2a}$  and root2 = $\frac{-b - \sqrt{b^{2} -4ac }}{2a}$

root 1 = $\frac{-3\sqrt{3} + \sqrt{3} }{2}$      and root2 = $\frac{-3\sqrt{3} - \sqrt{3} }{2}$

root1 = $-\sqrt{3}$             and root2 = $-2\sqrt{3}$

Similarly for 2) taking a = 1, b = $3\sqrt{3}$ and c = -30

root1 = $2\sqrt{3}$             and root2 = $-5\sqrt{3}$

hope this helps!!