Question

pls refer to ss . and pls reply

Answer 1

Answer:

bdnhdbrbhfnfbfjnrjjdf

Answer 2

Answer:

Since ∆bdc is a right angle triangle,

we have

bc²=bd²+dc²

»bc²=18²+24²

»bc²=324+576=900

»bc=30cm

similarly, as ∆Abc is a right angle triangle,

we have

Bc²=Ab²+Ac²

»30²=Ab²+Ab²

(Since Ab=Ac)

»2Ab²=900

»2Ab²=450

»Ab=21.21 I'm

And perimeter of the quadrilateral

Abcd=21.21+21.21+18+24=84.42cm