Pls refer to the image and solve fast
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Step-by-step explanation:
y= √a+√a+√a to infinity
on squareing both side
y²= a+√a+√a+√a to infinity
y²= a+y [y=√a+√a+√a to infinity]
y²-y-a= 0
it has real and distinct root so,
discriminant>1
D>1
b²-4ac>1
(-1)²-4•1•(-a)>1
1+4a>1
1+4a-1>1-1
4a>0
a>0
option (b) because if a>0 then a >all negative no.
#666
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