Question

Pls reply fast as soon as possible

Answer 1

Answer:

as we know a^3-b^3 =(a-b)(A2+ab+b2)

LHS: [(tan x-1)(tan2x+tanx+1)]/(tanx-1)

solve it first term will be cancelled

RhS :as sec2x=1+tan2x

then , tanex+1+tanx

LHS=RHS

I'm am new on this app n don't know how to use it so... I have difficulty in typical this mathematical portion ...