Question

pls say answer with solution then l will mark as brainlist
please say correct answer​

Answer 1

Given,

• d = 10 cm = 0.1 m
• friction coefficient(μ) = 0.5
• m = 5 kg
• g = 10 m\s²

(a) The work done by friction by which is in the opposite direction of motion is given by :

$\boxed{\bold{\omega_{fr} = -m\times g\times \mu_k \times d}}$

$\bold{\implies \omega_{fr} = -5\times 10\times 0.5\times 0.1}$

$\boxed{\bold{\therefore Frictional\:Force\:(\omega_{fr})=-2.5\:J}}$

(b) If the box moves at constant speed, So $\bold{\omega_h}$ is given by,

$\boxed{\bold{\omega_h=\omega_{net}-\omega_{fr}}}$

$\implies\bold{\omega_h=0-(-2.5)}$

$\boxed{\bold{\therefore Horizontal\:Force\:(\omega_{h})=2.5\:J}}$

Hence Option D is the correct answer..

Answer 2

Answer:

4) is answer dear friend