Question

pls say me these answers fast I will mark u as brilliant ​

Answer 1

3x-y+z =0

Squaring both side

$(3x +z)^{2} = y ^{2}$

9x² +z²+6xz = y²

9x²+z²-y²+6xz =0

Answer 2

Step-by-step explanation:

Answer of 2nd question

cubing on both sides

(2x-1/2x)^3=y^3

8x^3-1/8x^3-3(2x-1/2x)=y^3

8x^3-1/8x^3-6x+3/2x=y^3

hence, 8x^3-1/8x^3=6x-3/2x+y^3

hope this is helpful