Question

Pls see this pic and answer to this question

Answer 1

Solution:

Given: Initial ratio of acid and water => 4:3
After adding 10litres of acid,It becomes => 3:1

let the ratio on x be water(in litres),
let the ratio on y be acid(in litres),
then,
let the ratio be x and y   4x=3y=> 4x-3y=0...(i)
after adding 10 litres      4x+10 : 3y = 3:1
                                          (4x+10)/3=3y
                                           4x+10=9y
                                          4x-9y=-10...(ii)

(i)-(ii)=(4x-3y)-(4x-9y)=0-(-10)
               4x-3y-4x+9y=10
                                6y=10
                                  y=10/6
                                  y=5/3 litres of acid
(i)...  4x=3y
        4x=3(10/6)
        4x=10/2
        4x=5
          x=5/4 litres of water