pls send answer ........
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Given: x=rsinθcosϕ,y=rsinθsinϕ,z=rcosθ
Now, x
2
+y
2
+z
2
= r
2
sin
2
θcos
2
ϕ+r
2
sin
2
θsin
2
ϕ+r
2
cos
2
θ
= r
2
sin
2
θ(cos
2
ϕ+sin
2
ϕ)+r
2
cos
2
θ
= r
2
sin
2
θ+r
2
cos
2
θ
= r
2
(sin
2
θ+cos
2
θ)
= r
2
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