Math, asked by sachuskichus, 11 months ago

pls send answer fast

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Answered by bodakuntalacchanna
2

Answer:

p(x)=(k²-14) x²-2x-4

a=(k²-14), b=-2, c=-4

Sum of the zeroes=1

-b/a=1

-(-2)/(k²-14)=1

2=k²-14

0=k²-14-2

k²-16=0

k²=16

k=√16

k=±4

Therefore the required value of k may be 4 or -4

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