pls send answer fast
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Answer:
p(x)=(k²-14) x²-2x-4
a=(k²-14), b=-2, c=-4
Sum of the zeroes=1
-b/a=1
-(-2)/(k²-14)=1
2=k²-14
0=k²-14-2
k²-16=0
k²=16
k=√16
k=±4
Therefore the required value of k may be 4 or -4
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