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Answers
Step-by-step explanation:
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Answer:
FIRST ANSWER
In △PQR,
PQ=17 units,PR=11 units,QR=?,PS=13 units
We know that Apollonius's theorem relates the length of a median of a triangle to the lengths of its side. It states that "the sum of the squares of any two sides of any triangle equals twice the square on half the third side, together with twice the square on the median bisecting the third side".
Specifically, in any △ABC, AD is a median, then
AB²+AC²=2(BD²+CD²)
Using Apollonius's theorem,
PQ²+PR²=2(PS²+SR²)
17²+11²=2(13²+SR²)
289+121=2(169+SR²)
410=2(169+SR²)
(169+SR²)=205
SR²=36
SR=6 cm
Since S is the midpoint of QR
QR=2×SR
QR=12
QR=12 cm.
SECOND ANSWER
In △ABC , point D is the midpoint of side AB
AD=BD= 1/2 AB=5
CA²+CB²=2DC²+2AD² (by Apollonius theorem)
⇒7²+9²=2DC²+2(5²)
⇒49+81=2DC²+2(25)
⇒130=2DC²+50
⇒2DC²=80
⇒DC²=40
⇒DC=2√10
Hence, the length of the median drawn from point D to side AB is 2√10