Pls send me the answer of Q3 (Third question)
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∆ABC =∆DCB
Step-by-step explanation:
SUPPOSE
∆ACB and ∆DBC
Side AC=Side DC........[given]
Angle C = Angle C.....[Comman angle ]
Angle B=Angle B ............. [Comman angle]
then , ∆ABC =∆DCB ......[AA test of similarity ]
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