Question

pls send me the correct ​

Answer 1

Step-by-step explanation:

[9(5x-3) - 4(7-2x)] / (7-2x)(5x-3). = 0

(45x-27) - (28-8x) = 0 × (7-2x)(5x-3)

45x-27-28+8x = 0

53x-55 = 0

53x = 55

x = 55/53 = 1.03773585

Answer 2

Question 1 :

• $\sf\:\frac{9}{7-2x}-\frac{4}{5x-3}=0$

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Solution :

$\sf\:\frac{9}{7-2x}-\frac{4}{5x-3}=0$

LCM of ( 7-2x ) and ( 5x-3 ) = ( 7-2x ) ( 5x-3 )

$\sf\implies\:\frac{9(5x-3)-4(7-2x)}{(7-2x)(5x-3)}=0$

Multiplying the numbers

$\sf\implies\:\frac{45x-27-28+8x}{(7-2x)(5x-3)}=0$

Cross multiplying

$\sf\implies\:45x-27-28+8x=0 \times (7-2x)(5x-3)$

We know anything multiplied by 0 is 0

$\sf\implies\:45x-27-28+8x=0$

Arranging the terms

$\sf\implies\:45x+8x-27-28=0$

Proceeding with simple calculation

$\sf\implies\:45x+8x-55=0$

$\sf\implies\:53x-55=0$

Transposing -55 to RHS it becomes +55

$\sf\implies\:53x=55$

Transposing 53 to RHS it goes to the denominator

$\small{\underline{\boxed{\mathrm{\implies\:x=\frac{55}{53}}}}}$ $\bf\color{red}{⋆}$

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Question 2 :

• $\sf\:\frac{-8}{5x-2}-\frac{2}{3x+5}=0$ ‎

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Solution :

$\sf\:\frac{-8}{5x-2}-\frac{2}{3x+5}=0$

LCM of ( 5x-2 ) and ( 3x+5 ) = ( 5x-2 ) ( 3x+5 )

$\sf\implies\:\frac{-8(3x+5)-2(5x-2)}{(5x-2)(3x+5)}=0$

Multiplying the numbers

$\sf\implies\:\frac{-24x-40-10x+4}{(5x-2)(3x+5)}=0$

Cross multiplying

$\sf\implies\:-24x-40-10x+4= 0 \times (5x-2)(3x+5)$

We know anything multiplied by 0 is 0

$\sf\implies\:-24x-40-10x+4= 0$

Arranging the terms

$\sf\implies\:-24x-10x-40+4= 0$

Proceeding with simple calculation

$\sf\implies\:-34x-40+4= 0$

$\sf\implies\:-34x-36= 0$

Transposing -36 to RHS it becomes +36

$\sf\implies\:-34x=36$

Transposing -34 to RHS it goes to the denominator

$\sf\implies\:x=\frac{36}{-34}$

Reducing the fraction to lower terms

$\sf\implies\:x=\cancel{\frac{36}{-34}}$

$\small{\underline{\boxed{\mathrm{\implies\:x=\frac{-18}{17}}}}}$ $\bf\color{red}{⋆}$

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