Math, asked by evanjinvetharaja, 1 year ago

pls send the 22nd question

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Answered by leninviki
0
conjugate number
((2+√3)/(2-√3))*(2+√3)/(2+√3)
(2+√3)^2/(4-3)
(4+3+4√3)
(7+4√3) -----(1)
other one
((2-√3)/(2+√3))*(2-√3)/(2-√3)
(2-√3)^2/(4-3)
(4+3-4√3)
(7-4√3) -----(2)

((√3-1)/(√3+1))*(√3-1)/(√3-1)
(√3-1)^2/(3-1)
(3+1-2√3)/2
(4-2√3)/2
(2-√3) ------(3)

add (1),(2) (3)
7+4√3+7-4√3+2-√3
16-√3

a=16
b=-1

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