Question

pls send the written solution ​

Answer 1

Solution:

We have

$\rm \implies \: \dfrac{3t - 2}{4} - \dfrac{2t + 3}{3} = \dfrac{2}{ 3} - t$

Now take lcm

$\rm \implies \dfrac{3(3t - 2)}{4 \times 3} - \dfrac{4(2t + 3)}{3 \times 4} = \dfrac{2 \times 1}{ 3\times 1} - \dfrac{t \times 3}{1 \times 3}$

$\rm \implies \: \dfrac{9t - 6}{12} - \dfrac{8t + 12}{12} = \dfrac{2 - 3t}{3}$

$\rm \implies \: \dfrac{9t - 6 - 8t - 12}{ \cancel{12}} = \dfrac{2 - 3t}{ \cancel3}$

$\rm \implies \dfrac{t - 18}{4} = 2 - 3t$

$\rm \implies \: t - 18 = 4(2 - 3t)$

$\implies \rm \: t - 18 = 8 - 12t$

$\rm \implies \: t + 12t = 18 + 8$

$\implies \rm \: 13t = 26$

$\implies \rm \: t = \dfrac{26}{13}$

$\rm \implies \: t = 2$

Now check our answer

Take

$\rm \implies \: \dfrac{3t - 2}{4} - \dfrac{2t + 3}{3} = \dfrac{2}{ 3} - t$

and put t = 2

$\rm \implies \: \dfrac{3 \times 2 - 2}{4} - \dfrac{2 \times 2 + 3}{3} = \dfrac{2}{ 3} - 2$

$\implies \: \dfrac{6 - 2}{4} - \dfrac{4 + 3}{3} = \dfrac{2 -2 \times 3 }{3}$

$\implies \: \dfrac{4}{4} - \dfrac{7}{3} = \dfrac{2 - 6}{3}$

$\implies \: 1 - \dfrac{7}{3} = - \dfrac{4}{3}$

$\rm \implies \: \dfrac{3 - 7}{3} = - \dfrac{4}{3}$

$\rm \implies \: \dfrac{ - 4}{3} = \dfrac{ - 4}{3}$

Hence LHS = RHS

Answer 2

Answer:

-4/3 = -4/3

Step-by-step explanation:

.

Answer by @MrMysteryy