Math, asked by purisiddhant0350, 10 months ago

Pls simplify its urgent

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Answered by ROCKSTAR1OO8
0

Answer:

(x-2)(x-3)(x²-11x+18)/(x-9)(x²-5x+6)

=(x²-5x+6)(x²-11x+18)/(x-9)(x²-5x+6)

=(x²-11x+18)/(x-9)

denominator should not be 0

so x≠9

in numerator

x²-11x+18=0

x²-9x-2x+18=0

x(x-9)-2(x-9)=0

(x-9)(x-2)=0

x=9 and x=2

but we have proved that x≠9

so value of x is 2

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