pls slove sum no 6...
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Sum of internal angles of a triangle = 180°
∠P + ∠Q + ∠R = 180°
100° + 50° + ∠R = 180°
150° + ∠R = 180°
∠R = 180° - 150°
∠R = 30°
∴ The value of ∠R = 30°
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measure of all angles of triangle=180
6)100+50+angle R=180
150+angle R=180
angle R=180-150=30
7)we can also find using above formula=
angle P=40
6)100+50+angle R=180
150+angle R=180
angle R=180-150=30
7)we can also find using above formula=
angle P=40
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