Question

pls slove this as fast as fast u can

Answer 1

Step-by-step explanation:

$\frac{sinA + cosA}{sinA - cosA}$ × $\frac{sinA - cosA}{sinA + cosA}$

=$\frac{(sinA + cosA)^{2} + (sinA - cosA)^{2} }{(sinA + cosA)(sinA -cosA)}$

=$\frac{sin^{2}A +2sinAcosA +cos^{2}A + sin^{2}A -2sinAcosA +cos^{2}A}{sin^{2} A- cos^{2}A }$

=$\frac{2(sin^{2}A + cos^{2}A)}{sin^{2}A - cos^{2}A }$

=$\frac{2(1)}{sin^{2}A - cos^{2}A }$

=$\frac{2}{sin^{2}A - cos^{2}A }$   (first answer)

=$\frac{2}{sin^{2}A + 1 - cos^{2}A -1 }$                                                  

=$\frac{2}{sin^{2}A + sin^{2}A -1 }$

=$\frac{2}{2sin^{2}A -1 }$ (second answer)

from the first answer,

$\frac{2}{sin^{2}A - cos^{2}A }$  

=$\frac{2}{1 - cos^{2}A - cos^{2}A }$

=$\frac{2}{1 - 2cos^{2}A }$(third answer)    

Answer 2

Answer:

$good \: afternoon$