Question

pls slove this fast​

Answer 1

Let, p(x) = x³ + 3x² + 3x + 1

Also, g(x) = x + 1

Zero of g(x): x + 1 = 0

⇒ x = - 1

So, p(- 1) = (- 1)³ + 3(- 1)² + 3(- 1) + 1

⇒ p(- 1) = - 1 + 3(1) - 3 + 1

⇒ p(- 1) = - 1 + 3 - 3 + 1

⇒ p(- 1) = 0

Thus, the remainder is 0 {and g(x) is a factor of p(x)}.