Question

pls slove this question ​

Answer 1

$\bf\underline{\underline{\orange{Question:-}}}$

•The prices of two articles are in the ratio 3 : 4. If the price of the first article be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second article is

A. Rs. 40

B. Rs. 15

C. Rs. 30

D. Rs. 35

$\bf\underline{\underline{\orange{ Answer:-}}}$

Let price of two articles are 3X and 4X.

After increament price become

3.3X and (4X +4).

Now, according to question,

$\displaystyle\implies$3.3X/(4X +4) = 3/4

$\displaystyle\implies$13.2X = 12X + 12

$\displaystyle\implies$13.2 X - 12X = 12

$\displaystyle\implies$1.2X = 12

$\displaystyle\implies$X = 10.

So, original price of second article = 4X = 4•10 = Rs. 40.

Answer 2

Answer:

are you blind ?

i said don't answer if you can't