pls slove this question
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here is your answer ........
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x^3-8x^2+12x-5
Put x=1,then
p(1)=(1)^3-8*(1)^2+12*1-5
p(1)=1-8+12-5
p(1)=13-13=0
Put x=1,then
p(1)=(1)^3-8*(1)^2+12*1-5
p(1)=1-8+12-5
p(1)=13-13=0
MrCombat:
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