Math, asked by ASHVIK08, 4 months ago

pls solbe this now it is urgent​

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Answered by Cynefin
12

Required Answer:-

 \large{ \underline{ \boxed{ \purple{ \bf{Statement - 1}}}}}

Given that the length of the hall is 36 m and the breadth is 24 m long. Let h be the height of the hall.

Now:

  • We know the formula for finding the Lateral surface area of a cuboid i.e. 2h(l + b) unit².
  • Area to be papered = 2h(l + b) - 40 m²
  • Total cost = Total area × Cost

Plugging the values:

⇒ {2h(l + b) - 40} × Rs. 8.40 = Rs. 4704

⇒ 2h(36 + 24) - 40 = 560

⇒ 2h(60) = 560 + 40

⇒ 120h = 600

⇒ h = 5 m

\therefore Statement 1 is absolutely correct✓

━━━━━━━━━━━━━━━━━━━━

 \large{ \underline{ \boxed{ \purple{ \bf{Statement - 2}}}}}

Let the radius of the circle be r.

Then circumference will be 2πr and diameter of the circle will be 2r. Their difference is 154 cm.

The equation will be like:

⇒ 2πr - 2r = 154 cm

⇒ 2r(π - 1) = 154 cm

⇒ 2r(15/7) = 154 cm

⇒ r × 30/7 = 154 cm

⇒ r = 154 × 7/30 cm

⇒ r = 35.93 cm (approx.)

\therefore Statement 2 is incorrect.

━━━━━━━━━━━━━━━━━━━━

Statement 1 is true and Statement 2 is false. This is the correct alternative (Option C).

Answered by Anonymous
18

\; \; \; \;{\large{\rm{\underline{Required \: Solution}}}}

⚔️ Option C is absolutely correct means Statement - Ⅰ is true but Statement - Ⅱ is false.

Let's see how Option C is correct. Let's solve this question with full explanation.

\; \; \; \; \; \; \;{\sf{\boxed{\boxed{Statement - 1}}}}

Statement -

A hall is 36 metres long and 24 metres broad. If allowing areas of 40 metre² for doors and windows, the cost of papering the walls at Rupees 8.40 per square metre is Rupees 4704 then th height of the hall is 5 metres.

Given that -

\; \; \; \; \;{\bullet{\leadsto}} Length of the hall = 36 m

\; \; \; \; \;{\bullet{\leadsto}} Breadth of the hall = 24 m

\; \; \; \; \;{\bullet{\leadsto}} Allowing area is of 40 metre² for doors and windows.

\; \; \; \; \;{\bullet{\leadsto}} The cost of papering the walls at Rupees 8.40 per square metre is Rupees 4704

\; \; \; \; \;{\bullet{\leadsto}} The height of the hall is 5 metres.

To check -

\; \; \; \; \;{\bullet{\leadsto}} The statement is correct (according to the options).

Let's check -

[ Now according to the question, ]

↦ As we already know that the formula to find the Lateral Surface Area of cuboid is 2h(l+b) unit²

Here,

↗ H denotes height

↗ L denotes length

↗ B denotes breadth

↦ And as the question says that Allowing area is of 40 metre² so 2h(l+b) - 40 m² is the area to be allow.

↦ Henceforth, total cost = Total area × cost

[ Now let's put the values, ]

⇢ 2h(36+24) - 40 × 8.40 = 4704

⇢ 2h(36+24) - 40 × 560

⇢ 2h(60) = 560 + 40

⇢ 2h(60) = 600

⇢ 120h = 600

⇢ 60h = 300

⇢ 20h = 100

⇢ 2h = 10

⇢ h = 10/2

⇢ h = 5 metres

Henceforth, option A is true

\; \; \; \; \; \; \;{\sf{\boxed{\boxed{Statement - 2}}}}

Statement -

If the difference between the circumference and the diameter of a circle is 154 cm, then the radius of circle is 30.93 cm.

Given that -

\; \; \; \; \;{\bullet{\leadsto}} The difference between the circumference and the diameter of a circle is 154 cm

\; \; \; \; \;{\bullet{\leadsto}} The radius of circle is 30.93 cm.

To check -

\; \; \; \; \;{\bullet{\leadsto}} The statement is correct (according to the options).

Let's check -

[ Now according to the question, ]

↦ As we already know that the radius is denote as r henceforth, here circumference is 2πr and the diameter will be 2r and their difference is 154 cm.

2πr - 2r = 154 cm

π = 3.14 or 22/7 !

[ So now according to formed equation let's put the values, ]

⇢ 2πr - 2r = 154 cm

⇢ 2r(π-1) = 154 cm

⇢ 2r(15/7) = 154 cm

⇢ r × 30/7 = 154 cm

⇢ r = 154 × 7/30

⇢ r = 77 × 7/15

⇢ r = 35.93 cm

Henceforth, option B and D are incorrect.

\rule{150}{1}

Therefore, option C is correct.

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