Question

pls solve...1)Three consecutive even numbers are such that the largest of them is twice the smallest. Find the second largest number among the three.....pls someone tell in full method and explanation​

Answer 1

Answer:

Let 1st even number = 2x

2nd even number = 2x+2

3rd even number = 2x+2+2 = 2x+4

ATQ,

2x+4 = 2(2x)

2x+4 = 4x

4x-2x = 4

2x = 4

x = 4/2

x = 2

Smallest number = 2x = 2(2) = 4

Second largest number = 2x+2 = 2(2)+2 = 6

Largest number = 2x+4 = 2(2)+4 = 8

Answer 2

Step-by-step explanation:

Let the three consecutive numbers be n,n+1 ,n+2

n+4 = 2(n)

Therefore n = 4

The second largest no is n+2= 6

Hope this helps

Mark as brainliest

follow me