Question

pls solve 17 and 18 .both parts.

Answer 1

Hey there!

17.
$( \sqrt{32} - \sqrt{5} ) {}^{ \frac{1}{3} } ( \sqrt{32} + \sqrt{5} ) {}^{\frac{1}{3} }$

$(4 \sqrt{2} - \sqrt{5} ) {}^{ \frac{1}{3} } (4 \sqrt{2} + \sqrt{5} ) {}^{ \frac{1}{3} }$

$((4 \sqrt{2} - \sqrt{5} )(4 \sqrt{2} + \sqrt{5} )) {}^{ \frac{1}{3} }$

using (a-b)(a+b) = a²  - b² 

$(16 \times 2 - 5) {}^{ \frac{1}{3} }$

$27 {}^{ \frac{1}{3} }$
$(3 {}^{3} ) {}^{ \frac{1}{3} }$

= 3

18.
$( \frac{x {}^{m} }{x {}^{n} } ) {}^{l}( \frac{x {}^{n} }{x {}^{l} } ) {}^{m}( \frac{x {}^{l} }{x {}^{m} }) {}^{n}$

$(x {}^{m - n}) {}^{l} (x {}^{n - l} ) {}^{m} (x {}^{l - m} ) {}^{n}$

$x {}^{(m - n) {}^{l} } \times x {}^{(n - l) {}^{m} } \times x {}^{(l - m) {}^{n} }$

$x {}^{lm - ln} \times x {}^{mn - lm} \times x {}^{ln - mn}$


eliminating opposites

$x {}^{0}$

=1

Hope it helps!