Question

Pls solve 6th and 8th question .

Answer 1

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6.

$\tt{side \: of \: square \: plot} ,\mathscr{a} = \tt{220 \: m} \\ \\ \tt{area \: of \: square \: plot,} \: \mathscr {a}^{2} = \tt{(220 \: m)}^{2} \\ = \tt48400 {m}^{2} \\ \\ \tt{cost \: of \: levelling \: the \: plot \: at \: the }\\ \tt{rate \: of \: ₹15 \: per \: square \: meter }= \\\tt{ 48400 {m}^{2} \times 15 }\\ =\underline{\underline{\tt ₹7,26,000}}$

7.

$\tt{length\:of\:square\:tile,\:a = 16cm} \\ \tt{area \: of \: square \: tile ,\: {a}^{2} = {(16cm)}^{2} } \\ \tt{= 256 {cm}^{2} } \\ \\ \\\tt{ length \: of \: rectangular \: hall ,\: l \: } = \\ \tt 64m = \underline{6400cm}\\ \tt{ breadth \: of \: rectangular \: hall, \: b \: } =\\ \tt{40m = \underline{ 4000cm} }\\ \\ \tt{area \: of \: rectangular \: hall \: = l \times b} \\ = \tt{6400cm\times 4000cm}\\= \tt2560000{cm}^{2} \\ \\\tt{number \: of \: tiles \: required }= \\ \tt\frac{l \times b}{ {a}^{2} } = \\ \\\tt \frac{\cancel{256}^1 \: 0000 \: \cancel{{cm}^{2} }}{\cancel{256} \: {\cancel{ {cm}^{2}}} } =\tt\underline{\underline{10000 \: tiles}}$