pls solve above question in detail
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Given: x + y + z = 0
square on both sides,
x^2 + y^2 + z^2 + 2xy + 2yz + 2zx = 0
x^2 + y^2 + z^2 = -2(xy + yz + zx)
= -2{ x (y+z)+ yz} ---------(1)
x + y +z = 0
therefore, x = -(z + y)
x^2 + y^2 + z^2
to find: -------------------------
x^2 - yz
substitute (1) in the above equation
We'll get -2{ - (y+z)^2 + yz}
---------------------------
(y+z)^2 - yz
= 2
Therefore, the answer is 2;)
square on both sides,
x^2 + y^2 + z^2 + 2xy + 2yz + 2zx = 0
x^2 + y^2 + z^2 = -2(xy + yz + zx)
= -2{ x (y+z)+ yz} ---------(1)
x + y +z = 0
therefore, x = -(z + y)
x^2 + y^2 + z^2
to find: -------------------------
x^2 - yz
substitute (1) in the above equation
We'll get -2{ - (y+z)^2 + yz}
---------------------------
(y+z)^2 - yz
= 2
Therefore, the answer is 2;)
Jaanki:
wc
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