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Answer:
given: since PQRS is a rectangle, therefore, PS||RQ, PQ||SR, angle POQ is 110°
To find: i.angle PQO
ii.anglePSQ
iii.angle ORS
Solution: i. we are given angle POQ is 110°
thus, according to angle sum property, angle PQO+OPQ=180°-110°
thus, angles POQ+OPQ=70°
now, SR||PQ
thus, angles POQ and OPQ are adjacent angles and adjacent angles are equal
therefore, angle POQ=angle OPQ=35°
ii. angle POQ=35° (proved above)
angles POQ and PSQ are co interior angles(SR||PQ)and co interior angles sum upto 180°
thus, angle PSQ=180°-angle POQ
=180°-35°
angle PSQ=145°
iii. SR||PQ(given)
thus, angles QPO=ORS (alternate interior angles)
now, angle QPO=35°(proved above)
therefore, angle ORS=35°
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