Question

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Answer 1

i. oxidized

ii..oxidized

iii. reduced

iv. oxidized

v. oxidized

Answer 2

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a) $\sf Fe^{3+} -e\longrightarrow Fe^{2+}$ is a oxidation reaction

Reason

As we know that in an oxidation reaction there is a loss of electron so here from 3+ it goes to 2+ which means it has lost an electron so obviously it is a oxidation reaction

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b) $\sf S^{2-} +2e\longrightarrow S$ is a reduction reaction

Reason

So here we observe that there is a increase in the number of electrons (2- to +) which is a reduction reaction.i.e reduction is a increase in elections.

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c) $\sf O - 2e\longrightarrow O^{2-}$ is a oxidation reaction

Reason

As we saw already oxidation reaction is a increase in elections. So here the number of electrons reduce from + to -2 which means there is a reduction of 2 elections.

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d) $\sf Zn + 2e\longrightarrow Zn^{2+}$ is a reduction reaction

Reason

Here again there is a reduction,in other words the number of electrons have got reduced from + to 2+ which means there is an increase in the number of electrons.

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e) $\sf Cu^{2+} -2e \longrightarrow Cu$ is a oxidation reaction

Reason

So here we see that the number of electrons have gone down which means we it is a oxidation reaction.

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