Pls solve all these . I need it urgently. wrong answer will be reported so who know only they answer
the 1st one who answered right will be the brainlist answer
pls answer it fast I need it urgently
Answers
Answer:
I am taking theta as x
5 )
Sin ^ 2 x + Sin ^ 2 x * tan ^2 x
= Sin ^ 2 x ( 1 + tan ^2 x )
= Sin ^ 2 x (sec ^2 x )
= tan ^2 x
HENCE PROVED
6 )
tan ^2 x - sin^2 x
= sin^2 x /cos^2 x - sin ^2 x
= sin ^2 x ( 1/cos^2x - 1 )
= sin^2 x ( sec^2 x -1 )
= sin^2 x ( tan ^2 x )
HENCE PROVED
7)
cos ^2 x ( 1 + tan ^2 x ) + sin^2 x ( 1 + cot ^2 x )
= cos ^2 x + cos ^2 x * tan ^2 x + sin^2 x + sin^2 x * cot ^2 x
= cos ^2 x + sin^2 x + sin^2 x + cos ^2 x
= 1 + 1
= 2
HENCE PROVED
11)
(sec x - 1 )/(sec x + 1 )
= { ( 1/ cos x ) -1 } / { ( 1/cos x) + 1 }
=( 1 - cos x ) / (1 + cos x)
multiplying 1 + cos x on numerator and denominator
= 1 - cos ^2 x / (1 + cos x)^2
= sin ^ 2 x / (1 + cos x)^2
={ sin x / ( 1 + cos x ) } ^ 2
HENCE PROVED
12 )
(1 / sin x ) / { ( cos x / sin x) + tan x }
= (1 / sin x ) / { ( cos x / sin x) + (sin x / cos x) }
= (1 / sin x ) / {( cos ^2 x + sin ^2 x ) / sin x cos x }
= { (1 / sin x ) (sin x cos x ) } /1
= cos x
HENCE PROVED
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Answer:
refer to the attachment for the solution.
if it helps you then Mark as brainliest.