Question

pls solve and do the 7 one to i will mark you as brainliest and thanks to

Answer 1

Answer:

Number of chocolates Reeta has = 8

Number of chocolates Seema has = 40

Number of chocolates both Reeta and Seema has = 8+40

= 48 chocolates

Answer 2

Answer:

$\pink{ \sf \: Seema's \: \: chocolate \: = \: 16} \\ \green{ \sf Reeta's \: \: chocolate \: = x+8 \: = \: 16+8 \: = 24}$

Step-by-step explanation:

Let the seema's chocolate be x

Than Reeta's chocolate = x + 8

They have total chocolates = 40

$\underline {\text{According to the question}}$

x + x + 8 = 40

2x + 8 = 40

2x = 40-8

2x = 32

$x = \cancel \frac{32}{2}$

$\green{\sf \: x \: = \: 16}$

Seema's chocolate = 16

Reeta's chocolate= x+8 = 16+8= 24